In the high jump,the kinetic energy of an athlete is transformed into gravitatio

Question

In the high jump,the kinetic energy of an athlete is transformed into gravitationalpotential energy without the aid of a pole. With what minimum speedmust the athlete leave the ground in order to lift his center ofmass 2.04m and cross the bar with a speed of 0.690m/s? In the high jump,the kinetic energy of an athlete is transformed into gravitationalpotential energy without the aid of a pole. With what minimum speedmust the athlete leave the ground in order to lift his center ofmass 2.04m and cross the bar with a speed of 0.690m/s?

Explanation / Answer

   According to law of conservation ofenergy      Kmin   =   K   +   U    where    K and U are kineticand potential energy at highest point    (1/2)* m *vmin2   =   (1/2)* m * v2   +   m * g *h    vmin2   =   0.6902   +   9.8* 2.04    vmin   =   20.47             =   4.52   m/s

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