An air puck of mass 0.27 kg is tied to a string and allowed to revolve in a circ

Question

An air puck of mass 0.27 kg is tied to a string and allowed to revolve in a circle of radius 0.8 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.0 kg is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves.

(a) What is the tension in the string?
1 N

(b) What is the force causing the centripetal acceleration on the puck?
2 N

(c) What is the speed of the puck?
3 m/s

Explanation / Answer

Answered By "Mohsen" -------------------------------------------------------------------------------------------------------------------------------------------------------------------------- a) T = M g = 1.3 * 9.8 = 12.74 ? 12.7 N -------------------------------------------------------------------------------------------------------------------------------------------------------------------------- b) F = 12.7 N -------------------------------------------------------------------------------------------------------------------------------------------------------------------------- c) F = m v^2/R ==> v = ?(RF/m) = ?(0.8*12.74/0.35) = 5.40 m/s

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