An air puck of mass 0.220 kg is tied to a string and allowed to revolve in a cir
ID: 2149750 • Letter: A
Question
An air puck of mass 0.220 kg is tied to a string and allowed to revolve in a circle of radius 1.20 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.14 kg is tied to it as seen in the figure below.
The suspended mass remains in equilibrium while the puck on the tabletop revolves.
A) What is the tension in the string?
B) What is the force causing the centripetal acceleration of the puck?
C) What is the speed of the puck?
An air puck of mass 0.220 kg is tied to a string and allowed to revolve in a circle of radius 1.20 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.14 kg is tied to it as seen in the figure below. The suspended mass remains in equilibrium while the puck on the tabletop revolves. A) What is the tension in the string? B) What is the force causing the centripetal acceleration of the puck? C) What is the speed of the puck?Explanation / Answer
A) tension in the string = lower mass*g = 1.14*9.8 = 11.172 N B) This tension is causing the centripetal acceleration of the puck C) Centripetal acceleration = mv^2 / r = 11.172 0.22*v^2 /1.2 = 11.172 v = 7.8 m/s
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