Given a 36-inch RCP culvert. 80-fl long, laid on 05% grade and discharging to a
ID: 1709813 • Letter: G
Question
Given a 36-inch RCP culvert. 80-fl long, laid on 05% grade and discharging to a free outfall, i. e., there is a scour hole at the discharge end of the culvert If the design flow rate is 30 cfs, determine the headwater depth. If it is necessary you apply flow profile analysis, use the direct step method If, for the culvert in Problem 2, the discharge is doubled to 60 cfs, determine and plot the flow profile in the upstream channel, which has the following characteristics rectangular geometry, width = 8 feel; longitudinal slope = 0 5%. Manning's n = 0 065 Given a culvert road cross drain with the following characteristics 36-inch diameter RCP. 66-ft long, sloped at 0 8% The TW condition is a free outfall The upstream channel has the following characteristics rectangular geometry, base width- 9-ft; bed slope = 0 3%. Manning n-value = 0 065 When the flow is 50 cfs. determine and plot the flow profile upstream of the culvert cross dram. Given a 36-inch RCP storm sewer, 150-ft long, laid on 0 5% grade and discharging to a free outfall If the design flow rate is 26 cfs, determine the depth of flow at the upstream end (150-ft from the outfall) of the sewer Use the direct step method for flow profile analysisExplanation / Answer
Direct Step Method Q = 30 cfs n = 0.06 assumed S0 = 0.005 ft/ft = 1.1 assumed Hw = yd = 7.0 ft (starting water depth upstream of proposed culvert measured from stream bottom) Channel Geometry Inputs yd = 80.0 ft B = 10 ft D1 = 3 ft D2 = 3 ft S1 = 0.005 (ft H / ft V) Computed Area (A) (ft2) Computed Wetted Perimeter (P) (ft) Hydraulic Mean Radius (R) (ft) S2 = 0.005 (ft H / ft V) For yRelated Questions
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