Given Calculate the cell potential. (10 points) Cu (s) Cu2 (aq, 0.30 M) | Fe (aq

Question

Given Calculate the cell potential. (10 points) Cu (s) Cu2 (aq, 0.30 M) | Fe (aq, 0.1 M), Fe2 (aq, 0.2M) I Pt 10. A voltaic (Galvanic) cell is prepared by dipping a Ag wire in a 0.15 M Ag' solution and a Ni stri in a solution containing 0.2 M Ni2. Write the balanced chemical (redox) equation for this cell and calculate the cell potential, what is G for the cell. (10 points) 11. Electrolysis of a Cr3 solution to plate Cr metal is performed using a current of 1.5 amps. How many grams of Cr will plate out after 1 hour? (5 points)

Explanation / Answer

At anode : Cu -----> Cu+2 +2e-
At Cathode : Fe+3 + e- -----> Fe+2
E0 cell = E0 cathode - E0 anode
E0 cell = 0.77 - 0.34
E0 cell = 0.43 v

E cell = E0 cell -0.0591/n log (Ni+2)/(Ag+)^2
2Ag+ + Ni ------> 2Ag + Ni+2
E cell = (0.80 + 0.23) - 0.0591/2 log (0.2/(0.1^2))
E cell = 0.9915

W = Z * C * t ( Z = electrochemical equivalent of Cr, C = current passed through circuit, t = time period in sec)
W = 0.32333 * 1.5 * 1*60*60
W = 1745.982 g of Cr

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