a wheel of fortune has the numbers 1 through 50 painted on it .tickets numbered

Question

a wheel of fortune has the numbers 1 through 50 painted on it .tickets numbered 1 through 50 have been sold . The wheel will be rotated and the number on which the pointer lands will be the winning number. if the pointer stops on the line between two numbers, the wheel must be turned again, a prize of a new car will be awarded to the person whose ticket number matches the winning number.what is the probability that

1.ticket number 42wins?

2. ticket number 25,30, or 35 wins

3.a ticket between the numbers 26 and 39 wins

4.an even numbered ticket wins

5 ticket number 51 wins

Explanation / Answer

Total number of tickets = 50

1. P(ticket number 42 wins) = 1/50

2. P(ticket number 25,30, or 35 wins) = 1/50 + 1/50 + 1/50 = 3/50

3. P(a ticket between the numbers 26 and 39 wins) = P(27) + P(28) + P(29) + P(30) + P(31) + P(32) + P(33) + P(34) + P(35) + P(36) + P(37) + P(38) = 12/50

4. P(an even numbered ticket wins) = 25/50 = 1/2

5. P(ticket number 51 wins) = 0 (ticket number 51 doesn't exist)

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