Suppose that you are standing on a train accelerating at0.40 g . What minimum co

Question

Suppose that you are standing on a train accelerating at0.40g. What minimum coefficient of staticfriction must exist between your feet and the floor if you are notto slide?

A car can decelerate at -4.00 m/s2 without skidding when comingto rest on a level road. What would be the magnitude of itsdeceleration if the road were inclined at 14° uphill? Assume the same static frictioncoefficient.

A 22.0 kg box is released on a36.0° incline and accelerates downthe incline at 0.271 m/s2.Find the friction force impeding its motion. what is the KineticCoefficient

A 6520 kg helicopter acceleratesupward at 0.58 m/s2 whilelifting a 1190 kg car. and What is thetension in the cable (ignore its mass) that connects the car to thehelicopter?

Explanation / Answer

Formula for calculating the value of the coefficient ofminimum static friction between the feet and floor is                          = a / g                            = (0.40g) / g                            = 0.40 b) Deceleration (a) of the car = -4.00m/s2 Then the coefficient of static friction is a = - g                                                   -4.00m/s2 = -(9.8m/s2)                                                            = 0.41 When the car is moving up the hill then the formula for theacceleration (a) of the car is                    a = g(sin + cos)                        =(9.8m/s2)[sin14o +(0.41)(cos14o)]

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