Two identical loudspeakers are driven in phase by a commonoscillator at 800Hz an

Question

Two identical loudspeakers are driven in phase by a commonoscillator at 800Hz and face each other at a distance of 1.25m.Locate the points along the line joining the two speakers whererelative minima of sound pressure amplitude would beexpected. speed of sound = 343 m/s Two identical loudspeakers are driven in phase by a commonoscillator at 800Hz and face each other at a distance of 1.25m.Locate the points along the line joining the two speakers whererelative minima of sound pressure amplitude would beexpected. speed of sound = 343 m/s

Explanation / Answer

wavelength = 343/800 m = 0.42875 m let d = 1.25 m, x = the required point from one of the speakers.(0 x d) path difference = d - x - x = d - 2x destructive interference: d - 2x = (k + 1/2), x = [d - (k + 1/2)]/2 = 0.5178 - 0.2144k k = 2, x = 0.089 m k = 1, x = 0.303 m k = 0, x = 0.518 m k = -1, x = 0.732 m k = -2, x = 0.947 m k = -3, x = 1.161 m

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