A steel guitar string with diameter of 1.00 mm is strtchedbetween supports 800 m

Question

A steel guitar string with diameter of 1.00 mm is strtchedbetween supports 800 mm apart. Mass per unit length is 1.67 x10-3kg/m, fundamental frequency is 330 Hz, Initialtemperature is 30 0C, Young Modulus of steel is 2.0 x 1011Pa. 1. Calculate the tension in the string 2. If the temperatrue drops to 100C what will bethe tenstion in the string 3. To obtain the same fundamental frequency how many turns weneed to undo in the peg. Take one turn will ease 12mm A steel guitar string with diameter of 1.00 mm is strtchedbetween supports 800 mm apart. Mass per unit length is 1.67 x10-3kg/m, fundamental frequency is 330 Hz, Initialtemperature is 30 0C, Young Modulus of steel is 2.0 x 1011Pa. 1. Calculate the tension in the string 2. If the temperatrue drops to 100C what will bethe tenstion in the string 3. To obtain the same fundamental frequency how many turns weneed to undo in the peg. Take one turn will ease 12mm

Explanation / Answer

We know that                     v = / So that we get                    = v2 Where v = (331m/s)( T / 273K )                =(331m/s)(30+273K / 273K )               = 348.7 m/s            = v2                   = 348.7m/s * 348.7m/s * 1.67 x 10-3kg/m                   = 203 N b)          v =(331m/s)( T / 273K )                =(331m/s)(20+273K / 273K )               = 342.9 m/s                = v2                   = 342.9 m/s * 342.9m/s * 1.67 x 10-3kg/m                   = 196.3 N b)          v =(331m/s)( T / 273K )                =(331m/s)(20+273K / 273K )               = 342.9 m/s                =(331m/s)(20+273K / 273K )               = 342.9 m/s                = v2                   = 342.9 m/s * 342.9m/s * 1.67 x 10-3kg/m                   = 196.3 N

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