Two conducting spheres with diameters of 0.250m and 1.25m areseparated by a dist
ID: 1753251 • Letter: T
Question
Two conducting spheres with diameters of 0.250m and 1.25m areseparated by a distance that is large compared with the diameters.The spheres are connected by a thin wire and are charged to9.60micro-Coulomb. (a) How is the total charge shared? Charge of smallersphere,_______________ Charge of larger sphere,_________________ (b) What is the potential of the sysystem of spheres? NOTE: I got the answers for the smaller sphere of1.60micro-Coulomb and 8.00micro-Coulomb for the larger sphere andboth are correct. The only problem I do have now is the (b) part of the problem which I thought is to use:V=Q1/C1=Q1/Ke(d1). Please, I need an answer for this because it isdue at 11:00Pm tonight. Thank you for your help. Two conducting spheres with diameters of 0.250m and 1.25m areseparated by a distance that is large compared with the diameters.The spheres are connected by a thin wire and are charged to9.60micro-Coulomb. (a) How is the total charge shared? Charge of smallersphere,_______________ Charge of larger sphere,_________________ (b) What is the potential of the sysystem of spheres? NOTE: I got the answers for the smaller sphere of1.60micro-Coulomb and 8.00micro-Coulomb for the larger sphere andboth are correct. The only problem I do have now is the (b) part of the problem which I thought is to use:V=Q1/C1=Q1/Ke(d1). Please, I need an answer for this because it isdue at 11:00Pm tonight. Thank you for your help.Explanation / Answer
let Q be the totla chrge in hand if thery are connected by wire the surface charge density willremain constant q1 / A = q2 / A' A,A' are the surface areas of the small and big spheres and q1+q2 = Q from above relaions we can solve for the charge thatdeposted on each sphere q1 and q2 potential energy of a spehere of charged sphere V= kq / r k = 1/4 r= radius of sphere solving for q1 and q2 we can caculate potentialsof the two sphere.Related Questions
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