A 17.4 kg block is dragged over a rough, hor- izontal surface by a constant forc

Question

A 17.4 kg block is dragged over a rough, hor-
izontal surface by a constant force of 196 N
acting at an angle of angle 25.6? above the
horizontal. The block is displaced 80.4 m,
and the coefficient of kinetic friction is 0.247.
The acceleration of gravity is 9.8 m/s2 .

A)Find the work done by the 196 N force.
Answer in units of J.

B)Find the magnitude of the work done by the
force of friction. Answer in units of J.

C)What is the sign of the work done by the
frictional force?

D)Find the work done by the normal force. An-
swer in units of J.

E)What is the net work done on the block?
Answer in units of J.

Explanation / Answer

a) work=force*displacement work=(196cos()*80.4)=14211.44J b)Ff=mg=42.118N work=force*displacement=(42.118*80.4)=3386.322J c)Negative since the displacement is in the opposite direction ofthe force d)The work done by the normal force is zero since it isperpendicular to the motion e) Net work = 14211.44-3386.322=10825.118J

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