If you have a 1mM solution and .4uL is needed to make a 1uM solution (in final s

Question

If you have a 1mM solution and .4uL is needed to make a 1uM solution (in final solution of 400uL) but need 40uL to measure accurately. How would you make a dilution from the 1mM stock in order to still have a 1uM solution in the final solution of 400? If you have a 1mM solution and .4uL is needed to make a 1uM solution (in final solution of 400uL) but need 40uL to measure accurately. How would you make a dilution from the 1mM stock in order to still have a 1uM solution in the final solution of 400?

Explanation / Answer

Answer:

Stock: 1mM

First Dilution 10 fold: 100 uL from stock + 900 uL diluent = 1000 uL 0.1mM solution (100uM)

Second dilution 10 fold: 100 uL from first dilution tube + 900 uL diluent = 1000 uL 0.01mM solution (10uM)

Now we have 10 uM stock solution,

Stock = 10 uM

Required = 1 uM

Required volume = 400 uL

C1V1= C2V2

(stock)   (required)

V1=C2V2/C1

V1 = ( 1 X 400 uL )/ 10

=40 uL

40 uL of stock + 360 uL of diluent gives 1uM solution

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