A 2.0-kg ogject moving with a velocity of 5.0 m/s in thepositive x direction str

Question

A 2.0-kg ogject moving with a velocity of 5.0 m/s in thepositive x direction strikes and sticks toa     3.0-kg object moving with a speed of 2.0m/s in the same direction. How much kinetic energy is lost in thiscollision? a. 2.4 J b. 9.6 J c. 5.4 J d. 0.6 J e. 6.0 J A 2.0-kg ogject moving with a velocity of 5.0 m/s in thepositive x direction strikes and sticks toa     3.0-kg object moving with a speed of 2.0m/s in the same direction. How much kinetic energy is lost in thiscollision? a. 2.4 J b. 9.6 J c. 5.4 J d. 0.6 J e. 6.0 J

Explanation / Answer

Given m = 2 kg            v= 5 m / s           m' = 3 kg            v' = 2 m / s from law of conservation of momentum , m v + m ' v ' = ( m + m' ) V                                                              10 + 6 = 5 V                                                                      V = 3. 2 m / s Initial kinetic energy K = ( 1/ 2) m v ^ 2 + ( 1/ 2) m ' v ' ^ 2                                    = 31 J Final kinetic energy K ' = ( 1/ 2) ( m + m' ) V ^2                                     = 25.6 J kinetic energy lost = K - K '                             = 5.4 J from this wefind V value

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