A 23m long log of irregular cross section is lyinghorizontally supported by a wa

Question

A 23m long log of irregular cross section is lyinghorizontally supported by a wall at one end and a cable attached4.0m from the other end. The log weighs 7.5 x 10^3 N and thetension in the cable is 6.2 x 10^3 N. Where is the logs centerof gravity Please show allwork A 23m long log of irregular cross section is lyinghorizontally supported by a wall at one end and a cable attached4.0m from the other end. The log weighs 7.5 x 10^3 N and thetension in the cable is 6.2 x 10^3 N. Where is the logs centerof gravity Please show allwork

Explanation / Answer

A 23m long log of irregular cross section is lyinghorizontally supported by a wall at one end and a cable attached4.0m from the other end. The log weighs 7.5 x 10^3 N and thetension in the cable is 6.2 x 10^3 N. Where is the logs centerof gravity Please show all work

let the center of gravity of the log be x
now as per the equilibrium of the moments
7.5*103*x=6.2*103*(27-x)
solving x=12.222m from the wall

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