A series circuit consists of a 0.050µF capacitor, a 0.080 µFcapacitor, and a 420

Question

A series circuit consists of a 0.050µF capacitor, a 0.080 µFcapacitor, and a 420 V battery. Findthe charge for the following situations. (a) on each of the capacitors
1. µC (0.050µF capacitor)
2µC(0.080 µF capacitor)
(b) on each of the capacitors if they are reconnected in parallelacross the battery
3. µC (0.050µF capacitor)

                             . µC (0.080 µFcapacitor) (a) on each of the capacitors
1. µC (0.050µF capacitor)
2µC(0.080 µF capacitor)
(b) on each of the capacitors if they are reconnected in parallelacross the battery
3. µC (0.050µF capacitor)

                             . µC (0.080 µFcapacitor)

Explanation / Answer

First add in series
Ceq=c1c2/c1+c2=.0307F
Q=q1=q2=0.0307 x 420=12.92 uC is the answer for the firstpart
Vc1=12.92/0.05=258.4 volts, use q=CV, solve for q = .0307X258.4 = 7.93 uC
Vc2=12.92/0.08=161.5volts, use q =CV = .0307X161.5 = 4.95 uC

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