The radius of the earth\'s very nearlycircular orbit around the sun is 1.5x10 11
ID: 1764333 • Letter: T
Question
The radius of the earth's very nearlycircular orbit around the sun is 1.5x1011m Find the magnitude of the earth's velocity asit travels around the sun. Assume a year of 365 days. v= 30km/s (this i have alreadyfound) i need to: Find the magnitude of the earth's angularvelocity as it travels around the sun. Assume a year of 365days. Find the magnitude of the earth's centripetalacceleration as it travels around the sun. Assume a year of 365days. The radius of the earth's very nearlycircular orbit around the sun is 1.5x1011m Find the magnitude of the earth's velocity asit travels around the sun. Assume a year of 365 days. Find the magnitude of the earth's velocity asit travels around the sun. Assume a year of 365 days. v= 30km/s (this i have alreadyfound) i need to: Find the magnitude of the earth's angularvelocity as it travels around the sun. Assume a year of 365days. Find the magnitude of the earth's centripetalacceleration as it travels around the sun. Assume a year of 365days. Find the magnitude of the earth's centripetalacceleration as it travels around the sun. Assume a year of 365days.Explanation / Answer
. 01. distance = 2**r = 2**(1.5E11meters) = 942.4778E9 meters 02. velocity = d/t = [(942.4778E9 meters)/(365days)]*(1_day/86400 seconds) = 29.88577E3 meters/second . 03. tr = time to make 1 revolutionabout the sun = (365 days)*(86400 seconds/day) = 31536000seconds/revolution 04. = angular velocity = (2*radians/revolution)/(31536000 seconds/revolution) = 199.2385E-9 radians/second 05. Fcentripetal = (mass)(acceleration)=(mass)*(radius)*(2) a= (radius)*(2) 06. a = (1.5E11 meters)*(199.2385E-9radians/second)2 = 5.954397E-3meters/second2 = 0.00595m/s2 .Related Questions
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