My Notes O Ask Your 06 points 1 Previous Answers SerPSE9 4P.005 : are given by x

Question

My Notes O Ask Your 06 points 1 Previous Answers SerPSE9 4P.005 : are given by x 17.1 t and A golf ball is hit off a tee at the edge of a ciff. Its x and y coordinates as functions of time 3 .92t-4.90t, where x and y are in meters and t is in seconds. (a) Write a vector expression for the ball's position as a function of time, using the unit vectors 1 and J. (Glve the answer in terms of t.) By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector V as a function of time | 17.1/ ( 3.92-9.80t)/ | m/s (c) obtain the expression for the acceleration vector a as a function of time m/s? (d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t 3.03 s. r31.81i-33.108m v-17.1i-25.774 m/s a 9.80 m/s Need Help? Readn

Explanation / Answer

a)

Along the X-direction

X(t) = 17.1 t i

Along the Y-direction :

Yo = initial Position at t = 0 , = 0

Voy = initial velocity = 3.92 - 9.8 t

a = acceleration = - 9.8

Y(t) = Yo + Voy t + (0.5) a t2

Y(t) = 0 + (3.92 - 9.8 t) t + (0.5) (-9.8) t2

Y(t) = 3.92 t - 9.8 t2 - 3.92 t2

Y(t) = 3.92 t - 13.72 t2

so position is given as

r(t) = 17.1 t i + (3.92 t - 13.72 t2 ) j

b)

v(t) = dr(t)/dt = 17.1 i + (3.92 - 27.4 t) j

c)

a(t) = dv(t)/dt = 0 i - 27.4 j

d)

r(3.03) = 17.1 (3.03) i + (3.92 (3.03) - 13.72 (3.03)2 ) j = 51.8 i - 114.1 j  

v(3.03) = 17.1 i + (3.92 - 27.4 (3.03)) j = 17.1 i - 79.1 j

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.