A solenoid has cross-sectional area A, length 1 and n turns. A second solenoid h

Question

A solenoid has cross-sectional area A, length 1 and n turns. A second solenoid has twice the cross-sectional area, twice the length and twice the number of turns as compared to the first solenoid The ratio of the inductance of the first to the second solenoid is 1:2 1:4 0 1:1 Submit You currently have O submissions for this question. Only 2 submission are allowed You can make 2 more submissions for this question. (Survey Question) 2) Briefly explainyour answer to the previous question. Submit You currently have 0 submissions for this question. Only 2 submission are allowed You can make 2 more submissions for this question.

Explanation / Answer

1)L1/L2 = 1/4

2)Explanation:

We know that the inductance of a solenoid is given by:

L = u n^2 A/l

L1 = u n^2 A/l

L2 = u (2n)^2 2 A/2 l

L1/L2 = u n^2 A/l x 2 l/ u 4 n^2 a A = 1/4

Hence, L1/L2 = 1/4

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.