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Chrome File Edit View History Bookmarks People Window Help 57% L)- "aus. Tue 10:28 AM Q OE Baby Driver xWileyPLUS Ahmad Secure l https://edugenwileyplus.com/edugen/student/mainfr.uni Apps V WileyPLUSDifferential calcul s lyi University of South D Apple iCloud Yahoo Bing W wikipedia R Facebook y Twitter-LinkedIn D The Weather Channel Yelp » Other Bookmarks WileyPLUS Hlliday, Fundamentals of Physics, 10e Calculus-based Physics I ⅈ (PH 201-202) Home Read, Study & Practice Gradebook ORION Downloadable eTextbook Assianment> Open Assignment FULL SCREEN PRINTER VERSION BACK ASSIGNMENT RESOURCES Chapter 15, Problem 060 201-20 040 Your answer is partially correct. Try again. The suspension system of a 1600 kg automobile "sags" 8.0 cm when the chassis is placed on it. Also, the oscillation amplitude decreases by 59% each cycle. Estimate the values of (a) the spring constant k and (b) the damping constantb for the spring and shock absorber system of one wheel, assuming each wheel supports 400 kg. 49.000 N/m 078 (b) Number 648.70 Review Score Review Results by Study LINK TO TEXT Question Attempts: 2 of 6 usedSAVE FOR LATER SUBMIT ANSWER ights Reserved. A Division of John Wiley & Sons Ins Version 4.24.2.4 httos:/fedugen wleyplus.com/edugen/shared/assignment/test/ag istuni?id-asnmt210074

Explanation / Answer

Solution) (a) Given mass m=1600 kg

Sags by x= 8cm=0.08m

Spring constant K=?

We have F= Kx

mg= Kx

K=mg/x =1600×10/0.08

K=2×10^5 N/m

(b) amplitude decreases by 59%

We have the formula e^(-bT/2m)=0.41

But time period T=2×3.14(m/K)^(1/2)

T=2×3.14(1600/200000)^(1/2)

T=0.561s

bT/2m=log(1÷0.41)

b×0.561/(2×1600)=0.387

b=2207.48kg/m

Therefore damping constant b=2207.48 kg/m

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