A 121.8 N carton is pulled up a frictionless baggage ramp inclined at 33.0 above

Question

A 121.8 N carton is pulled up a frictionless baggage ramp inclined at 33.0 above the horizontal by a rope exerting a 70.8 N pull parallel to the ramp's surface. The carton travels 5.25 malong the surface of the ramp.

Part A

Calculate the work done on the carton by the rope.

Express your answer using three significant figures.

Part B

Calculate the work done on the carton by the gravity.

Express your answer using three significant figures.

Part C

Calculate the work done on the carton by the normal force of the ramp.

Express your answer using three significant figures.

Part D

What is the net work done on the carton?

Express your answer using three significant figures.

Part E

Suppose that the rope is angled at 47.6 above the horizontal, instead of being parallel to the ramp's surface. How much work does the rope do on the carton in this case?

Express your answer using three significant figures.

i need the answers with details please as soon as possible

Explanation / Answer

W = F.d = F d cos(theta)

(A) W = (70.8) (5.25) (cos0)

W = 371.7 J

(B) W = (121.8)(5.25) (cos(90 + 33))

W = - 348.3 J

(c) theta= 90 deg

W = 0

(d) Net work done = 371.7 - 348.3

= 23.4 J

(e) W = (70.8)(5.24) (cos(47.6-33))

= 360 J

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