Object A has mass m\'A 1 0 kg and initial momentum ,- kg·m/s. what is the moment

Question

Object A has mass m'A 1 0 kg and initial momentum ,- kg·m/s. what is the momentum of object B just after the collision? kg m/s At this point we've learned all that we can from applying the momentum principle. Next we'll see what additional information we can obtain by using the energy principle. Before the collision, whet was the magnitude of the momentum of object A? kg ms Before the collision, what was the kinetic energy of object A? Remember that you can calculate kinetic energy not only rrom K = (1/2)/ 2 but more directly from K-(1/2)Ipl3n. Before the collision, what was the magnitude of the momentum of object B? Before the collision, what was the kinetic energy of object B? After the collision, what was the magnitude of the momentum of object A? After the collision, what was the kinetic energy of object A? After the collision, what was the magnitude of the momentum of object B? After the collision, what was the kinetic energy of object B? Before the collision, what was the total kinetic energy of the system? After the collision, what was the totel kinetic energy of the system? kg mfs kg mys kg m/s What kind of collision was this? (Remember that an "elastic" collision is one where the final value of the total kinetic energy is equal to the initial value of the total kinetic energy.) o not enough information to decide inelastic elastic Assume that all of the energy is either kinetic energy or thermal energy. Calculate the increase of thermal energy ot the two objects. 5a,thermal EB,thermal- In the preceding analysis, what assumption did you make about (energy flow from surroundings into the system due to a temperature difference)? can be ignored because colliding objects never get hot. Q was negligible because the process lasted only a short time

Explanation / Answer

1)The total intial momentum of the system will be:

Psys i = (22 + 6, -8 + 6, 0 + 0) = (28, -2, 0)kg-m/s

Hence, Psys i = (28, -2, 0)kg-m/s

2)from the conservation of momentum,

Fnet-T = (0,0,0) N-s

3)Again from conservation of momentum, it should be equal to the intial momentum of the system

Psys f = (28, -2 , 0)kg-m/s

4)The initial and final total momentum is:

P = (28, - 2 , 0) kg-m/s

Pa = (18, 5 , 0) kg-m/s

So that of B will be:

Pb = (28 - 18 , -2 - 5 , 0) = (10 , -7 , 0)kg-m/s

Hence, Pb = (10 , -7 , 0) kg-m/s

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