3. (10 points) Circle ONLY ONE of the answer choices in the questions below I: T
ID: 1782499 • Letter: 3
Question
3. (10 points) Circle ONLY ONE of the answer choices in the questions below I: Two objects are fired into the air with the same speeds, and the drawing shows the projectile motions. Projectile 1 reaches the greater height, but projectile 2 has the greater range. Which one is in the air for the greatest amount of time? A. Projectile 1, becouse it travels higher than projectile 2 B. Projectile 2, because it has the greater range. C. Both projectiles spend the same amount of time in the air D. Projectile 2, because it has the smaller initial speed and, therefore, travels more slowly than projectile 1 E Not enough information to determine answer II: A tennis ball is thrown upward at an angle and follows a parabolic path before it hits the ground which statement is true about the ball when it is at the highest point in its tr jectory? A The bars velocity and acceleration are both zero. B. The ball's velocity is perpendicular to its C. The balls velocity is not zero, but its acceleration is zero. D. The ball's velocity is zero, but its acceleration is not zero. E. The horizontal and vertical components of the balr's velocity are equal. acceleration III: You stand on a spring scale on the floor of an elevator. Of the following, the scale shows the highest reading when the elevator: A moves downward with increasing speed B. moves downward with decreasing speed C. remains stationary D. moves upward with decreasing speed E moves upward at constant speedExplanation / Answer
I) option A projectile 1 travel higher than projectile 2, because it attained more vertical height.
Vertical height and time of flight depends on vertical component of projectile velocity.
II) Option B the velocity and acceleration are perpendicular at maximum height of obliquely projected ball.
At highest point velocity is in horizontal direction and acceleration is vertically downwards.
III) Option B moves down with decreasing speed i.e., with moves down with deceleration.
The effective weight is M(g+a)
Mmass of the ball, g acceleration due to gravity and
a acceleration downwards.
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