What is the maximum number of 100-W lightbulbs you can connect in parralel in a

Question

What is the maximum number of 100-W lightbulbs you can connect in parralel in a 120-V home circuit without tripping the 20A circuit breaker?

THE ANSWER IS D.

If €1 = 4.0 V, 2 = 12.0 V, R = 42, R2 = 12 N, C = 3 puF, Q= 18 JC, and = 2.5 A, difference V- VG? |din Va - Vo - JR% + E-TR, FE, de Va- V = -Ikz - % + E2-IRI PE Va - = -30 - 6 + 12 + 4-10 b-mTº -30 V B) 30 v C) 5.0 V D) -5.0 V E) -1.0 V 2. JAt7 = 0 the switch S is closed with the capacitor uncharged. If C = 30 uF, &= 30 V, and R rate is energy being stored in the capacitor when /= 2.0 mA? (2410 C- 30 DE Chasse problem E = R= 5 KR I=2 A C = R: 5 KR QCA=CV. 1-RC) TU)= *e°E KA A) 32 mW B) 40 mW C) 44 mW (D) 36 mW E) 80 mW QCE) = CE-IR | 3. What is the maximum number of 100-W lightbulbs you can connect in parallel in a 120-V ho without tripping the 20-A circuit breaker? 19 P= /00 9 32 O 23 P., -(120X20) = 240 w E 12 R = lay w Page 1 24 23 A) 120 = / 20A -I P= VI

Explanation / Answer

Power = Voltage*Current

Pmax = 120*20 = 2400 W

Power of 1 bulb = 100 W

No. of bulb = Pmax/P1 = 2400/100 = 24 bulbs,

Now if we used 24 bulbs then circuit will be tripped, So without tripping we can using maximum 23 circuit.

Let me know if you have any doubt.

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