A mass of 1.56 kilograms is placed on a horizontal frictionless surface against

Question

A mass of 1.56 kilograms is placed on a horizontal frictionless surface against an uncompressed spring with spring constant 1090.3N/m. The mass is pushed against the spring until the spring is compressed a distance 0.4 and then released. How high (vertically) in m does the mass rise from the original height before it stops (momentarily) A mass of 1.56 kilograms is placed on a horizontal frictionless surface against an uncompressed spring with spring constant 1090.3N/m. The mass is pushed against the spring until the spring is compressed a distance 0.4 and then released. How high (vertically) in m does the mass rise from the original height before it stops (momentarily)

Explanation / Answer

All the spring PE stored in the spring is converted to the gravitational PE .

So, 0.5*k*x^2 = mgh

where , k = spring constant = 1090.3 N/m

x = 0.4 m

m = 1.56 kg

g = 9.8 m/s2

h = height reached from the point it is released from the spring

So, 0.5*1090.3*0.4^2 = 1.56*9.8*h

So, h = 5.71 m

So, the height it rised from the original height = 5.71 - 0.4 = 5.31 m

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