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Two particles are moving along a straight line starting beginning from x(0) = 0

ID: 1856183 • Letter: T

Question

Two particles are moving along a straight line starting beginning from x(0) = 0 with a velocity of v(0) = 10 at time t = 0. Both the particles begin to decelerate. The magnitude of acceleration of the first particle is directly proportional to the time, t and that of the second particle is directly proportional to the speed of the particle. (a) At time t = 2 which particle has the higher velocity? (b) Which particle comes to rest (zero velocity) first and at what time does this occur? Assume the constants of proportionality to be 1. [

Explanation / Answer

for the 1st particle


deceleration = Kt

k =1


deceleration = t


v = u -at


v = 10 - t^2


at t = 2


v = 10 - 4


v = 6 m/s



for body 2


deceleration = Kv


k =1

a = v

v = u - at


v = 10 - vt


v(1+t) = 10


v = 10/(1+t)


at t = 2


v = 10/3


v = 3.333 m/s




lets finfd the time when v becomes zero for both


for 1st


10 - t^2 = 0


t = 3.16 s



for 2nd


0 = 10/(1+t)


so this will take infinite time



so the 1st body comes to rest earlier than the 2nd one

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