Two particles are moving along a straight line starting beginning from x(0) = 0
ID: 1856183 • Letter: T
Question
Two particles are moving along a straight line starting beginning from x(0) = 0 with a velocity of v(0) = 10 at time t = 0. Both the particles begin to decelerate. The magnitude of acceleration of the first particle is directly proportional to the time, t and that of the second particle is directly proportional to the speed of the particle. (a) At time t = 2 which particle has the higher velocity? (b) Which particle comes to rest (zero velocity) first and at what time does this occur? Assume the constants of proportionality to be 1. [Explanation / Answer
for the 1st particle
deceleration = Kt
k =1
deceleration = t
v = u -at
v = 10 - t^2
at t = 2
v = 10 - 4
v = 6 m/s
for body 2
deceleration = Kv
k =1
a = v
v = u - at
v = 10 - vt
v(1+t) = 10
v = 10/(1+t)
at t = 2
v = 10/3
v = 3.333 m/s
lets finfd the time when v becomes zero for both
for 1st
10 - t^2 = 0
t = 3.16 s
for 2nd
0 = 10/(1+t)
so this will take infinite time
so the 1st body comes to rest earlier than the 2nd one
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