156 l b man leaps off the circular platform with a velocity of v m / p = 6 f t /

Question

156lb man leaps off the circular platform with a velocity of vm/p = 6ft/s , relative to the platform.(Figure 1 )Determine the angular velocity of the platform afterwards. Initially the man and platform are at rest. The platform weighs 305

lb and can be treated as a uniform circular disk.

156lb man leaps off the circular platform with a velocity of vm/p = 6ft/s , relative to the platform.(Figure 1 )Determine the angular velocity of the platform afterwards. Initially the man and platform are at rest. The platform weighs 305 lb and can be treated as a uniform circular disk.

Explanation / Answer

Here Angular Momentm remains Conserved

mvr = Iw

mvr = (0.5*MR^2 + mr^2)*w

w = (156*6*8)/(0.5*305*10^2 + 156*8^2)

= 0.2967

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