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TmagItuge of 4.0 N/C? (3.0 m) Two small identical condi cting spheres are placed

ID: 1875085 • Letter: T

Question

TmagItuge of 4.0 N/C? (3.0 m) Two small identical condi cting spheres are placed with their centers 0.30 m apart. One is given a charge of 1.0 ×10. C the other a charge of-3.0 xi0" C. (a) Find the electrostatic force exerted on one sphere by the other. (3.0 x 10 "N, attraction) (b) The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached, where both spheres have the same charge.(1.0x 10 N, repulsion) Two charges are arranged as shown in Figure. Find the direction and magnitude of the electric field at the origin. (1.3 x 10 N, 58° clock wise from +x) 2.0cm Three point charges are arranged at the corners of a square of side 0.500 m, as shown in Figure. What is the potential V at the vacant corner (point A), taking V-0 at a great distance? (3.47 x 10 v) (b) What work should be done by the field to move +2.00 C point charge from infinity to vacant corner A? (-6.94 x 10-J) 10.0 HC 4.00 HC 5.00 uC

Explanation / Answer

4.

Given that,

r = 0.3 m

q1 = 1*10^(-9) C

q2 = -3*10^(-9) C

(a)

Electrostatic force on one sphere by other,

F = kq1q2 / r^2

F = 9*10^9*1*10^(-9)*3*10^(-9) / (0.3)^2

F = 3*10^(-7) N (force of attraction)

(b)

When spheres are connected by wire,

Total charge is equally divided b/w them

q1 = q2 = (1*10^(-9) - 3*10^(-9)) / 2 = -1*10^(-9) C

F = kq1q2 / r^2

F = 9*10^9*(1*10^(-9))^2 / (0.3)^2

F = 1*10^(-7) N (repulsive force)

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