With friction turned on, set the initial velocity of the box to 2.5 m/s, the coe

Question

With friction turned on, set the initial velocity of the box to 2.5 m/s, the coefficient of friction to 0.15, and the mass to 0.7 kg. Assume the acceleration due to gravity has a magnitude of 9.8 m/s2.

(a) What is the magnitude of the frictional force acting on the block while it is in motion?

(b) What is the acceleration of the box? Define to the right as the positive direction, as in the simulation.

(c) What is the distance traveled by the box before coming to rest?

(d) How much time passes before the block comes to rest?

References-Google Chrome X a Secure https://edugen.wileyplus.com/edugen/player/references/index.uni?mode-help8xlinkobject c06- References FN Position 8 Clear Trace 2 Initial velocity (m/s): 4(m/s) 2.5 Velocity Coefficient of kinetic friction: 2.5 2 1.5 0.15 0.1 0.6 0.5 Block mass (kg) 4 (s 0.7 Acceleration 2 4 (s) O) Friction On Friction Off m/s 2) Concept Questions Notes Audio Intro CLOSE

Explanation / Answer

a] Friction force = uN = umg = 0.15*0.7*9.8 = 1.029 N

b] acceleration of the box a = -ug =  -0.15*9.8 = - 1.47 m/s^2

c] distance travelled s = v^2/2a = 2.5^2/[2*1.47] = 2.126 m

d] time passed t = v/a = 2.5/1.47 = 1.7 s

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