An electric point charge of Q1 = 8.45 nC is placed at the origin of the real axi

Question

An electric point charge of Q1 = 8.45 nC is placed at the origin of the real axis. Another point charge of Q2-1.77 nC is placed at a position of p = 3.06 m on the real axis. At which position can a third oint charge of q-6.36 nC be placed so that the net electrostatic force on it is zero? Submil AnswTries 0/12 Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero? Submit Aneuwar Tries 0/12

Explanation / Answer

Given,

q1 = 8.45 nC ; q2 = 1.77 nC ; q3 = -6.36 nC ; p = 3.06 m

We know that

F = k q1q2/r^2

for net force to be zero

F23 = F13

k q2q3/r12^2 = k q1q3/r13^2

8.45 nC/d^2 = 1.77 nC/(3.06 - d)^2

8.45 (3.06 - d)^2 = 1.77 d^2

8.45 (9.36 + d^2 - 6.12d ) = 1.77 d^2

79.1 + 8.45 d^2 - 51.71d = 1.77 d^2

6.68 d^2 - 51.71 d + 79.1 = 0

d = 5.64 ; 2.1 m

d = 2.1 as its between charges

b)Remains the same.

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