#60 nc ball after speed of 40.0 m/s. TE hitting it. Ignoring air resistance, det

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#60

nc ball after speed of 40.0 m/s. TE hitting it. Ignoring air resistance, determine tespiu Ol I 59. mmh A 67.0-kg person jumps from rest off a 3.00-m-hi straight down into the water. Neglect air resistance. rest 1.10 m under the surface of the water. Determine the ma of the average force that the water exerts on the diver. This for ball leaves the bat and is 25.0 m above the point of impact r the She comes to nonconservative al ir 60. At a carnival, you can try to ring a bell by striking a target with a 9.00-kg hammer. In response, a 0.400-kg metal piece is sent upward toward the bell, which is 5.00 nm above. Suppose that 25.0% of the ham rmer's kinetic energy is used to do the work of sending the metal piece upward. How fast must the hammer be moving when it strikes the target so that the bell just barely rings? a* 61. ssm A truck is traveling at 11.1 m/s down a hill when the brakes on all four wheels lock. The hill makes an angle of 15.0° with respect to the

Explanation / Answer

Figure out the energy difference needed to be imparted to the piece to just strike the bell first. Gravitational potential energy is : U=mgh

so,
0.4kg * 5m *g = 19.6J, which means we need the hammer's kinetic energy to be 19.6J / 0.25 (since only 25% of the hammer's kinetic energy is used to send the bell upward) = 78.4N

Kinetic energy is 1/2mv^2 = 78.4N, and we know the m of the hammer is 9kg, so we rearrange the formula to get v^2 = 2*78.4J/9kg, so v = sqrt(2*78.4/9) = 4.17m/s

Check it: does 0.5*9kg*(4.17m/s)^2 = 0.25*0.4kg*5m*9.8m/s^2

It does, so the our method works, 1/2mv^2 (for the hammer) = mgh/0.25 (for the piece)

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