A mass of 8 kg is resting on a horizontal, frictionless surface. Force 1 is appl

Question

A mass of 8 kg is resting on a horizontal, frictionless surface. Force 1 is applied to it at 21 degrees below the horizontal, force 2 has a magnitude of 18 N and is applied When these ramagniude magnitude anagnitude of is aplied vertically downward, force 3 has a magnitude of 5 N and is applied vertically upwards, and force 4 has a magnitude of 18 N and is applied in the-x direction to the object. When these forces are applied to the object, the object moves 10 meters in the +x direction and the velocity of the object is 8 m/s in the +x direction. What is the normal force acting on the mass in Newtons? Fs F4 F: F1

Explanation / Answer

Using 3rd equation of motio

a= v^2/(2d)

a= 8^2/(2*10)= 3.2 m/s^2

Considering equilibrium of forces along x axis

ma = F1 cos x - F4

8*3.2= F1 cos 21- 18

F1= 46.7 N

Normal force given by

N= mg+ F2+ F1 sin x -F3

= 8*9.8+ 46.7 sin 21+ 18 -5

= 108.135 N

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Commemt in case any doubt.. good luck

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