An electron is released from rest at a distance of 0.520 m from a large insulati

Question

An electron is released from rest at a distance of 0.520 m from a large insulating sheet of charge that has uniform surface charge density 4.30×1012 C/m2 .

Part A

How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 7.00×102 m from the sheet?

Express your answer to three significant figures and include the appropriate units.

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Part B

What is the speed of the electron when it is 7.00×102 m from the sheet?

Express your answer to three significant figures and include the appropriate units.

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Explanation / Answer

= surface charge density = 4.30×1012 C/m2 .

E = electric field = / (2 o) = 4.30×1012 / (2 x 8.85 ×1012 ) = 0.243 N/C

q = charge on electron = 1.6 x 10-19 C

Force on the electric = F = qE = 1.6 x 10-19 x 0.243 = 0.388 x 10-19 N

d = distance travelled = 0.520 - 0.07 m = 0.45 m

a)

Work done = F d = 0.388 x 10-19 x 0.45 = 1.746 x 10-20 J

b)

work done appears as the kinetic energy and is given as

KE = work done

(½) m V2 = 1.746 x 10-20

(0.5) (9.1 x 10-31) V2 = 1.746 x 10-20

V = 1.958 x 105 m/s

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