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A 3.48g bullet moving at 300m/s enters and stops in an initially stationary 3.50

ID: 1902242 • Letter: A

Question

A 3.48g bullet moving at 300m/s enters and stops in an initially stationary 3.50kg wooden block on a horizontal frictionless surface. What's the speed of the bullet/ block combination? Express your answer to two significant figures and include the appropriate units. upsilon = What fraction of the bullet's kinetic energy was lost in this perfectly inelastic collision? f = How much work was done in stopping the bullet? Express your answer to two significant figures and include the appropriate units. w =

Explanation / Answer

a)Conserving momentum,

0.00348*300=3.50348*v

v=0.30m/s

b)Loss in KE=0.5m1u2-0.5Mv2=156.44J

Initial energy=0.5m1u2=156.6J

Loss%=99.9%

c)Work done in stopping the bullet=KE of bullet=-160J

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