Consider a disk rotating at the same spot, and consequently the reference point

Question

Consider a disk rotating at the same spot, and consequently the reference point on its circumference (*) makes a circular motion with the constant angular frequency , i.e., theta(t) = omega t. Fig. 7 plots the height of the reference point as a function of angle . Fig. 7 height of reference point as the disk rotates. Assume that at the reference point is at point P when t = 0, and it takes 2.5 s to come to point Q, which is vertically straight above the center of the circle. Find the period, frequency, and angular frequency of the circular motion of the reference point. Replot the height of the reference point on the t (time) axis, as opposed to the theta-axis. Indicate the point(s) where the graph crosses the t-axis in number (in s).

Explanation / Answer

solution: angle covered = p/2 rad , time taken = 2.5 seconds SO, angular velocity ? = p/2 / 2.5 = p/5 rad/sec T = 2p/? = 10 sec f = 1/T = 0.1 Hz.........................................Ans

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