Consider a disk rotating at the same spot, and consequently the reference point

Question

Consider a disk rotating at the same spot, and consequently the reference point on its circumference (*) makes a circular motion with the constant angular frequency . i.e., theta(t) = omega t. Fig. 7 plots the height of the reference point as a function of angle theta. Fig. 7 height of reference point as the disk rotates. Assume that at the reference point is at point P when t = 0. and it takes 2.5 s to come to point Q. which is vertically straight above the center of the circle. Find the period, frequency, and angular frequency of the circular motion of the reference point.

Explanation / Answer

period = 2.5 frequency = 1/2.5 = 0.4 angular frequency = 2pi/2.5

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