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A 13.0 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended fr

ID: 1911612 • Letter: A

Question

A 13.0 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended from a scale and immersed in water as shown in the figure below. The 12.0 cm dimension is vertical, and the top of the block is 5.75 cm below the surface of the water.

(a) What are the magnitudes of the forces acting on the top and on the bottom of the block due to the surrounding water? (Use P0 = 1.0130 10^5 N/m^2.)

Ftop = _______________ N ???

Fbottom = __________________ N ???

(b) What is the reading of the spring scale? _____________________ N ???

A 13.0 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended from a scale and immersed in water as shown in the figure below. The 12.0 cm dimension is vertical, and the top of the block is 5.75 cm below the surface of the water. (a) What are the magnitudes of the forces acting on the top and on the bottom of the block due to the surrounding water? (Use P0 = 1.0130 10^5 N/m^2.) Ftop = _______________ N ??? Fbottom = __________________ N ??? (b) What is the reading of the spring scale? _____________________ N ???

Explanation / Answer

Ftop=Ptop*A=(1.013*105+1000*9.81*5.75/100)*100/10000=1018.64 N

Fbottom=Pbottom*A=(1.013*105+1000*9.81*17.75/100)*100/10000=1030.41 N

b)reading on scale=mg+Ftop-Fbottom=13*9.81+1018.64-1030.41=115.76 N

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