A 13.0 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended fr

Question

A 13.0 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended from a scale and immersed in water as shown in the figure below. The 12.0 cm dimension is vertical, and the top of the block is 5.80 cm below the surface of the water. What are the magnitudes of the forces acting on the top and on the bottom of the block due to the surrounding water? (Use P_0 = 1.0130 times 10^5 N/m^2.) F_top = 1018.39  N F_bottom = 1013.17 N What is the reading of the spring scale? 100 Your response differs from the correct answer by more than 10%. Double check your calculations. N Show that the buoyant force equals the difference between the forces at the top and bottom of the block. (Do this on paper. Your instructor may ask you to turn in this work.)

Explanation / Answer

b) Apparent weight = Actual weight - Buoyant force

Spring reading = mg – [FTop - FBottom] = 13.0*9.8 - [1018.39 - 1013.17] = 122.18 N

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