Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In a plant leaf color, leaf shape, and plant height are controlled by three link

ID: 191839 • Letter: I

Question

In a plant leaf color, leaf shape, and plant height are controlled by three linked genes. Wildtype plants are normal height with pointed, green leaves. Triple mutant plants are dwarf (d) with round (r), white (w) leaves. A female heterozygous for all three mutations is testcrossed and the following progeny phenotypes were observed:

wildtype

116

dwarf

350

dwarf, round

4

dwarf, round, white

120

round, white

325

round

35

white

3

dwarf, white

47

a. What are the parental genotypes?

b. Which gene is in the middle?

c. Construct a genetic map showing distances between adjacent genes.

d. Calculate the interference observed in this cross.

wildtype

116

dwarf

350

dwarf, round

4

dwarf, round, white

120

round, white

325

round

35

white

3

dwarf, white

47

Explanation / Answer

Answer:

Explanation:

a. What are the parental genotypes?

Female: dRW/Drw

Male: drw/drw

b. Which gene is in the middle? Gene "r""

c. Construct a genetic map showing distances between adjacent genes.

d----------24.3cM----------r-------8.9cM--------w

d.. Calculate the interference observed in this cross: 0.68

Hint: Always recombinant genotypes are smaller than the non-recombinant genotypes.

Hence, the parental (non-recombinant) genotype is dRW / Drw.

Wildtype (DRW)

116

Dwarf (dRW)

350

dwarf, round (drW)

4

dwarf, round, white (drw)

120

round, white(Drw)

325

Round(DrW)

35

White(DRw)

3

dwarf, white(dRw)

47

1).

If single crossover occurs between d & R..

Normal combination: dR / Dr

After crossover: dr/Dr

dr progeny= 4+120=124

DR progeny = 3+116=119

Total this progeny = 243

The recombination frequency between d&R = (number of recombinants/Total progeny) 100

RF = (243/1000)100 = 24.3%

2).

If single crossover occurs between R & W..

Normal combination: RW / rw

After crossover: Rw/rW

Rw progeny= 3+47=50

rW progeny = 4+35=39

Total this progeny = 89

The recombination frequency between R&W = (number of recombinants/Total progeny) 100

RF = (89/1000)100 = 8.9%

3).

If single crossover occurs between d & W..

Normal combination: dW / Dw

After crossover: dw/DW

dw progeny= 120+47=167

DW progeny = 116+35=151

Total this progeny = 318

The recombination frequency between d&W= (number of recombinants/Total progeny) 100

RF = (318/1000)100 = 31.8%

Recombination frequency (%) = Distance between the genes (cM)

d----------24.3cM----------r-------8.9cM--------w

Expected double crossover frequency = (RF between h & w) * (RF between w & b)

= 24.3% * 8.9% = 0.022

The observed double crossover frequency = 3+4 / 1000 = 0.007

Coefficient of Coincidence (COC) = Observed double crossover frequency / Expected double crossover frequency

= 0.007 / 0.022

= 0.32

Interference = 1-COC

= 1-0.32 = 0.68

Wildtype (DRW)

116

Dwarf (dRW)

350

dwarf, round (drW)

4

dwarf, round, white (drw)

120

round, white(Drw)

325

Round(DrW)

35

White(DRw)

3

dwarf, white(dRw)

47

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote