In a plant species with just 7 \"S\" alleles for the self-incompatibility gene,
ID: 206111 • Letter: I
Question
In a plant species with just 7 "S" alleles for the self-incompatibility gene, a plant breeder uses pollen from one plant to pollinate six other plants. Only one of the plants that were pollinated produced seeds. They do some genetic testing and find that the 6 plants that were pollinated have the self-incompatibility genotypes of S1S2 , S4S6 , S3S4 , S2S5 , S3S7 and S1S3.
Given what you know about this set-up, what is the genotype of the plant that made the pollen, and what is the genotype of the plant that this pollen did successfully fertilize (the one that eventually produced seeds)?
The parent of the pollen has a genotype of S2 S5, and the plant that got fertilized and produced seeds is S3 S7.Explanation / Answer
From the above data it, answer is = The parent of the pollen has a genotypeof S2S3 and plant that got fertilized and produced seeds is S4S6.
Because: above mention is a type of sporophytic incompatibility. it occurs when one of the 2 S alleles of the pollen producing sporophyte matches one of the S alleles of the stigma. pollen exine are specially responsible for this type of incompatibility. From all given options- when pollen Parent is S2S3 it will show self incopatibility to all other plants every plant have either S2 or S3 allele which will cause incompatibility toward them except S4S6.
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