In the long jump, an athlete launches herself at an angle above the ground and l

Question

In the long jump, an athlete launches herself at an angle above the ground and lands at the same height, trying to travel the greatest horizontal distance. Suppose that on earth she is in the air for time t, reaches a maximum height h, and achieves a horizontal distance D.

If she jumped in exactly the same way during a competition on Mars, where g on Mars is 0.379 of its earth value, find her time in the air, max height, and horizontal distance. Express your answer in terms of t,h, and D, respectively.

Since there are no values given besides g on Mars, I guess I have to solve for the appropriate variable but I don't know which formulas to use.

Explanation / Answer

gMars=9.8*0.379=3.7142 m/s2==>vox=Vo*cos()==>voy=Vo*sin()

total flight time is voy/gMars *2 equals time up to max ht, same amt of

time to fall back to same start levelvoy/gMars*2

max ht voy2/(2*gMars)==>x=vox*voy/gMars *2

total flight time voy/gMars *2

max ht voy2/(2*gMars)

x distance vox*voy/gMars *2

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