Engineers are designing a system by which a falling mass m, imparts kinetic ener

Question

Engineers are designing a system by which a falling mass m, imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire around the rim of the drum. There is no appreciable friction in the axle of the drum and everything starts from rest. The system is being tested on Earth but is to be used on Mars, where the acceleration due to gravity is 3.71 m/s2. In the Earth tests when m is set for 15 kg and allowed to fall through 5.00 m, it gives 250 J of kinetic energy to the drum. If operated on Mars, through what distance would the mass need to fall in order to give the same kinetic energy to the drum?

Explanation / Answer

we know, change in potential=mgh=15*9.8*5 =735J out of 735J ,250J is converted to kinetic energy efficiency=250/735. now in mars let height be h' 250=m*3.71*h'*250/735 h'=13.2m hence it should fall by 13.2m

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