A certain child\'s near point is 13.5 cm; her far point (with eyes relaxed) is 1

Question

A certain child's near point is 13.5 cm; her far point (with eyes relaxed) is 125 cm. Each eye lens is 2.00 cm from the retina.
(a) Between what limits does the power of this lens-cornea combination vary?



Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. diopters (lower bound) to


Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. diopters (upper bound)


(b) Calculate the power of the eyeglass lens the child should use for relaxed distance vision. Is the lens converging or diverging?
diopters, and the lens is

Explanation / Answer

1 / o + 1 / i = 1 / f f = i * o / (i + o) = 1 / P At the near point f = 13.5 * 2 / (2 + 13.5) = 1.74cm P = 1 / .0174 = 57.4 diopters At the far point f = 129 * 2 / (2 + 129) = 1.97cm P = 1 / .0197 = 50.8diopters For the image to be at -129 cm when the object is atinfinity -1 / 129 = 1 / f f = -129 cm P = -1 / 1.29= -.775 diopters The lens is concave (negative focal length)(

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