<p>An object weighting 600.0 g in air is immersed in water after being tied to a
ID: 1975998 • Letter: #
Question
<p>An object weighting 600.0 g in air is immersed in water after being tied to a string connected to a balance. The scale now reads 546.9g. When immersed in oil, the object weighs 557.5g.<br />a- Find the loss of weight(in gram of weight) when completely submersed in water.<br />b- Find the volume of the object in cm3 and in m3.<br />c-Find the density of the object. (kg/m3)<br />d-Find the buoyant force in N on the object.<br />e-Find the mass of the oil displaced by the object when completely submersed in oil.<br />f-find the density of oil.</p>Explanation / Answer
assuming that g is 10m/s/s and water density is 1000kg/m/m/m and neglecting air bouyancy
mass of water displaced = w = (600-546.9)/10 kg : vol water displaced = vol object = (600-546.9)/10/1000 m^3
mass of oil displaced = o = (600-557)/10 kg
mass of object = 600/10 kg
(a) 600/10/((600-546.9)/10/1000 ) kg/m^3
(b) (600-557)/10/((600-546.9)/10/1000 ) kg/m^3
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