This is part three of a three part question, please show work and, if you could,

Question

This is part three of a three part question, please show work and, if you could, please explain.

Question: If the rope breaks under a tension of 6.00 * 103 N, where would the knight be located in relation to the bridge? (i.e. how far does the knight get to in meters on the bridge when the rope breaks)

Description: A Knight rides slowly out of the castle and on a 12.0 m long drawbridge that passes over the moat. A rope attached to the castle and the end of the drawbridge forms an angle = 30.0 degrees when the drawbridge is horizontal. The bridge itself has a uniform mass of 400 kg. the Knight is a total mass of 550 kg.

Explanation / Answer

let the knight goes x distance from the entrance when the rope breaks,
so, similar treatment of the question as in part 1 yields,

550g*(x) + 400g*(l/2) = T*sin30*(l) where l =12 m
so, 500g(x) + 400g*12 = (6*10^3)*sin30*(12)
so, x= 2.32m   <--------answer(part 3)

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