An electron moves in the magnetic field B^rightarrow = 0.500 i^hat T with a spee

Question

An electron moves in the magnetic field B^rightarrow = 0.500 i^hat T with a speed of 0.500 times 10^7 m/s in the directions shown in the figure. For each what is magnetic force F^rightarrow on the electron? (figure 1) Part A Express vector F^rightarrow in the form of F_x, F_y, F_z, where the x, y, and z components are separated by commas. F^rightarrow = ______ Part B Express vector F^rightarrow in the form of Fx, F_y, F_z, where the x, y, and z components are separated by commas. F^rightarrow = ______­_

Explanation / Answer

here,

B = 0.50 i

part a)

v = 5 *10^6 (-j) m/s

force on the electron

F = -1.602 *10^-19 * ( 5 *10^6 (-j)) X (0.50 i)

F = - 4 *10^-13 k N

F = ( 0 , 0 , - 4 *10^-13 ) N

part B)

the velocity is

v = 5 *10^6 * (-cos(45) j + sin(45) k)

Now, for the force on electron

F = -1.602 *10^-19 * ( 5 *10^6 * (-cos(45) j + sin(45) k)) X (0.50 i)

F = -2.83 *10^-13 * ( k + j)

the force is F = (0 , -2.83 *10^-13 , -2.83 *10^-13 ) N

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