8.) (a) A straight current-carrying wire of finite, non-zero mass is inserted in

Question

8.) (a) A straight current-carrying wire of finite, non-zero mass is inserted into a region of space where a strong magnetic field is directed vertically downward. Can the wire be oriented so that it is suspended in mid air by the magnetic force? If so, how? If not, why not? Explain your answer clearly.

(b) A particle with a charge -a is moving from left to right (west to east) with a velocitv v in a region where a uniform magnetic field B is directed perpendicular to the paper and coming out towards the reader. How should an electric electric field E be directed so that the force it applies to the particle can balance the magnetic force the particle experiences due to B? Explain clearly. 0 0 oBo oo o 0 o O o O

Explanation / Answer

8)

a) magnetic field , B = - k

as the direction of magnetic force must be upwards as this is parallel to the magnetic field

as magnetic force is always perpendicular to the magnetic field

this is not possible to suspend the wire using magnetic field

b)

direction of velocity = i

magnetic field = B k

direction of magnetic force = - q * V X B

direction of magnetic force = - i X k

direction of magnetic force = j

Now, for the direction of electric field needed

direction of electric field = -(direction of magnetic force)/(-q)

direction of electric field = - (j)/(-1)

direction of electric field = j

the direction of magnetic field needed is from down to upwards (towards the top of plane )

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