8. [1pt] Inside most old fashioned (\"tube\") TV sets you will find two parallel

Question

1. 8. [1pt]
2. 
   
3. Inside most old fashioned ("tube") TV sets you will find two parallel charged plates designed to accelerate electrons. Let's assume an electron is accelerated in the uniform field

E (E = 8.70 Inside most old fashioned ("tube") TV sets you will find two parallel charged plates designed to accelerate electrons. Let's assume an electron is accelerated in the uniform field E (E = 8.70 times 103 N/C) between the plates shown in the figure. (The thickness of the plates themselves is negligible, despite how fat they might look in this picture.) The electron starts from rest near the negative plate and passes through a tiny hole in the positive plate. In designing this system, how far apart do you need to space the two plates such that the electron exits with a kinetic energy of 1.61 times 10-17 J? (As we will see later in this course, this energy is enough to generate light when the electron finally hits the phosphors on the front screen!) I got 1.16 times 10^-14m but that isn't right. m=9.11 times 10^-31kg

Explanation / Answer

Let d be the distance between the plates

Work done = gain of kinetic energy, KE

or, KE =e Ed = 1.6x10^-19 * 8.70 * 10^3 * d

or, 1.61 * 10^-17 = 1.6x10^-19 * 8.70 * 10^3 * d

or d = = (1.61 * 10^-17) / ( 1.6x10^-19 * 8.70 * 10^3)

or, d = 0.01157 m

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