Click-and-drag the particles to move them left or right. The particle on the lef

Question

Click-and-drag the particles to move them left or right. The particle on the left is confined to the region to the left of the origin; the particle on the right is confined to the region to the right of the origin. In this simulation, you can see the graph of the electric field on the x-axis as a function of position, as well as the electric potential on the x-axis as a function of position. On the graph, the electric field is shown as positive if the net field at that position is directed to the right, and the field is shown as positive if the field is directed left. Using the sliders, you can adjust the positions of the charged particles as well as their charges.

Explanation / Answer

(a) If I move from one side of a charged particle to other side, the sign of electric field flips because the electric field is a vector while the electric potential has the same sign as it is a scalar quantity. so option (ii) and (iii) are correct.

Further as the electric field is the slope of electric potential vs distance curve so if the slope is zero, the electric field will be zero. So option (vi) is true.

(b)

Option (i) is true.

Option (ii) is false.

Option (iii) is false.

Option (iv) is true.

Option (v) is false.

Option (vi) is true.

Option (vii) is false.

Option (viii) is False.

Option (ix) True.

Option (x) is false.

Explanation from option (v) to (x) is q is proportional to r^a where a is 2 in case of electric field and 1 in case of electric potential.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.