A charge 5.01 nC is placed at the origin of an xy -coordinate system, and a char

Question

A charge 5.01 nC is placed at the origin of an xy-coordinate system, and a charge -2.03 nC is placed on the positive x-axis at x = 3.97 cm . A third particle, of charge 6.03 nC is now placed at the point x = 3.97 cm, y = 3.02 cm .

Find the x-component of the total force exerted on the third charge by the other two.

Find the direction of the total force acting on the third charge.

Please show clear work! Thank you!

Find the y-component of the total force exerted on the third charge by the other two.

Find the magnitude of the total force acting on the third charge.

Explanation / Answer

Y component of force = 8.98*109*6.03*10-9*5.01*10-9*sin37.26/(0.04988)2 - 8.98*109*6.03*10-9*2.03*10-9/(0.0302)2

                                                = 66.015*10-6 - 120.52*10-6

                                                 = -54.505 *10-6 N   ------------------towards -ve y axis

X component of force = 8.98*109*6.03*10-9*5.01*10-9*cos37.26/(0.04988)2

                                                = 86.78*10-6 N ------------------towards +ve x axis

Net magnitude of force = 102.477*10-6 N

Direction = - tan-1(54.505/86.78)

               = - 32.132 degrees from + x axis clockwise

                                                

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