A 2200 kg car traveling to the right at 32 m/s is chasing a second car of the sa

Question

A 2200 kg car traveling to the right at 32 m/s is chasing a second car of the same mass that is traveling to the right at 10 m/s.
(a) If the two cars collide and stick together, what is their speed just after the collision?
m/s

(b) What fraction of the initial kinetic energy of the cars is lost during this collision?
Where does it go?
No kinetic energy is lost.
It is returned to the Universe.    
It is transformed into heat, sound, and the deformation of the metal.
It is converted to momentum.
It is transmitted to the road.

Explanation / Answer

given that mass of car1  M = 2200kg speed of the car u1 = 32 m/s mass of second car m = 2200kg speed of the car = u2 = 10 m/s after stick together   both car moving with same velocity from the ineleastic collission    Mu1 + mu2 = ( M+m)V     V = 21 m/s
for the second part     K/ K( intial) = K( final) - K( intial)/ K( intial)                          = K( final)/ K( intial) -1                           = 1/2 * ( 2m) V^2/ 1/2 *mv(1)^2 + 1/2 * mv(2)^2 - 1                         = 2 V^2/ v(1)^2 + v(2)^2 - 1 where V = v(1) + v(2)/2                = 32+ 10/2 = 21m/s              = 2( 21m/s)^2/ ( 32m/s)^2 + ( 10 m/s)^2 - 1             = - 0.215 21.5% of the intial kinetic energy is transefered into heat, sound and deformation of metal.

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